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42254501520053 is a prime number
BaseRepresentation
bin10011001101110001001001…
…00011011010001010110101
312112121111020212021122000202
421212320210203122022311
521014244204342120203
6225511241112050245
711620533636552524
oct1146704443321265
9175544225248022
1042254501520053
1112511040598809
1248a5257093985
131a767756a7344
14a611b35604bb
154d420ad02388
hex266e248da2b5

42254501520053 has 2 divisors, whose sum is σ = 42254501520054. Its totient is φ = 42254501520052.

The previous prime is 42254501519987. The next prime is 42254501520079. The reversal of 42254501520053 is 35002510545224.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33807910204849 + 8446591315204 = 5814457^2 + 2906302^2 .

It is a cyclic number.

It is not a de Polignac number, because 42254501520053 - 210 = 42254501519029 is a prime.

It is a super-2 number, since 2×422545015200532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42254501519989 and 42254501520016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42254501520853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21127250760026 + 21127250760027.

It is an arithmetic number, because the mean of its divisors is an integer number (21127250760027).

Almost surely, 242254501520053 is an apocalyptic number.

It is an amenable number.

42254501520053 is a deficient number, since it is larger than the sum of its proper divisors (1).

42254501520053 is an equidigital number, since it uses as much as digits as its factorization.

42254501520053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240000, while the sum is 38.

The spelling of 42254501520053 in words is "forty-two trillion, two hundred fifty-four billion, five hundred one million, five hundred twenty thousand, fifty-three".