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4232345214013 = 7604620744859
BaseRepresentation
bin111101100101101011011…
…011101101110000111101
3112222121102102012111121221
4331211223123231300331
51023320320333322023
613000151302153341
7614530313512450
oct75455333556075
915877372174557
104232345214013
111391a225998a4
1258430ba22851
132491543259a7
14108bbd107497
157515ddab85d
hex3d96b6edc3d

4232345214013 has 4 divisors (see below), whose sum is σ = 4836965958880. Its totient is φ = 3627724469148.

The previous prime is 4232345214011. The next prime is 4232345214137. The reversal of 4232345214013 is 3104125432324.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4232345214013 - 21 = 4232345214011 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4232345214013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4232345214011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302310372423 + ... + 302310372436.

It is an arithmetic number, because the mean of its divisors is an integer number (1209241489720).

Almost surely, 24232345214013 is an apocalyptic number.

It is an amenable number.

4232345214013 is a deficient number, since it is larger than the sum of its proper divisors (604620744867).

4232345214013 is an equidigital number, since it uses as much as digits as its factorization.

4232345214013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604620744866.

The product of its (nonzero) digits is 69120, while the sum is 34.

The spelling of 4232345214013 in words is "four trillion, two hundred thirty-two billion, three hundred forty-five million, two hundred fourteen thousand, thirteen".

Divisors: 1 7 604620744859 4232345214013