4233130000933 has 2 divisors, whose sum is σ = 4233130000934. Its totient is φ = 4233130000932.

The previous prime is 4233130000907. The next prime is 4233130000951. The reversal of 4233130000933 is 3390000313324.

4233130000933 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3702210836769 + 530919164164 = 1924113^2 + 728642^2 .

It is a cyclic number.

It is not a de Polignac number, because 4233130000933 - 2⁵ = 4233130000901 is a prime.

It is a super-3 number, since 3×4233130000933³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4233130000895 and 4233130000904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4233130000973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565000466 + 2116565000467.

It is an arithmetic number, because the mean of its divisors is an integer number (2116565000467).

Almost surely, 2^{4233130000933} is an apocalyptic number.

It is an amenable number.

4233130000933 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233130000933 is an equidigital number, since it uses as much as digits as its factorization.

4233130000933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 31.

The spelling of 4233130000933 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, nine hundred thirty-three", and thus it is an aban number.