4233130101341 has 2 divisors, whose sum is σ = 4233130101342. Its totient is φ = 4233130101340.

The previous prime is 4233130101301. The next prime is 4233130101353. The reversal of 4233130101341 is 1431010313324.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2787013219225 + 1446116882116 = 1669435^2 + 1202546^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4233130101341 is a prime.

It is a super-3 number, since 3×4233130101341³ (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4233130101341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4233130101301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565050670 + 2116565050671.

It is an arithmetic number, because the mean of its divisors is an integer number (2116565050671).

Almost surely, 2^{4233130101341} is an apocalyptic number.

It is an amenable number.

4233130101341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233130101341 is an equidigital number, since it uses as much as digits as its factorization.

4233130101341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 4233130101341 its reverse (1431010313324), we get a palindrome (5664140414665).

The spelling of 4233130101341 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, one hundred one thousand, three hundred forty-one".