Base | Representation |
---|---|
bin | 1100010100011110110… |
… | …10111111101001011101 |
3 | 1111110122102010011011101 |
4 | 12022033122333221131 |
5 | 23413421112411331 |
6 | 522244534553101 |
7 | 42404043146641 |
oct | 6121732775135 |
9 | 1443572104141 |
10 | 423313013341 |
11 | 153587184379 |
12 | 6a05a808791 |
13 | 30bc25035aa |
14 | 166ba490c21 |
15 | b028438061 |
hex | 628f6bfa5d |
423313013341 has 2 divisors, whose sum is σ = 423313013342. Its totient is φ = 423313013340.
The previous prime is 423313013327. The next prime is 423313013351. The reversal of 423313013341 is 143310313324.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 397599608025 + 25713405316 = 630555^2 + 160354^2 .
It is a cyclic number.
It is not a de Polignac number, because 423313013341 - 211 = 423313011293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (423313013351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211656506670 + 211656506671.
It is an arithmetic number, because the mean of its divisors is an integer number (211656506671).
Almost surely, 2423313013341 is an apocalyptic number.
It is an amenable number.
423313013341 is a deficient number, since it is larger than the sum of its proper divisors (1).
423313013341 is an equidigital number, since it uses as much as digits as its factorization.
423313013341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 423313013341 its reverse (143310313324), we get a palindrome (566623326665).
The spelling of 423313013341 in words is "four hundred twenty-three billion, three hundred thirteen million, thirteen thousand, three hundred forty-one".
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