Base | Representation |
---|---|
bin | 100111011111010000… |
… | …110010000010110001 |
3 | 11001102221212201100021 |
4 | 213133100302002301 |
5 | 1143314002032423 |
6 | 31251204123441 |
7 | 3030502441555 |
oct | 473720620261 |
9 | 131387781307 |
10 | 42400424113 |
11 | 16a88a30223 |
12 | 8273996581 |
13 | 3cc9489268 |
14 | 20a32db865 |
15 | 11825e395d |
hex | 9df4320b1 |
42400424113 has 4 divisors (see below), whose sum is σ = 42590560768. Its totient is φ = 42210287460.
The previous prime is 42400424093. The next prime is 42400424137. The reversal of 42400424113 is 31142400424.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-42400424113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (42400421113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95067993 + ... + 95068438.
It is an arithmetic number, because the mean of its divisors is an integer number (10647640192).
Almost surely, 242400424113 is an apocalyptic number.
It is an amenable number.
42400424113 is a deficient number, since it is larger than the sum of its proper divisors (190136655).
42400424113 is a wasteful number, since it uses less digits than its factorization.
42400424113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 190136654.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 42400424113 its reverse (31142400424), we get a palindrome (73542824537).
The spelling of 42400424113 in words is "forty-two billion, four hundred million, four hundred twenty-four thousand, one hundred thirteen".
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