42403114214113 has 2 divisors, whose sum is σ = 42403114214114. Its totient is φ = 42403114214112.

The previous prime is 42403114214059. The next prime is 42403114214117. The reversal of 42403114214113 is 31141241130424.

42403114214113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41727246073569 + 675868140544 = 6459663^2 + 822112^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-42403114214113 is a prime.

It is a super-3 number, since 3×42403114214113³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (42403114214117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21201557107056 + 21201557107057.

It is an arithmetic number, because the mean of its divisors is an integer number (21201557107057).

Almost surely, 2^{42403114214113} is an apocalyptic number.

It is an amenable number.

42403114214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

42403114214113 is an equidigital number, since it uses as much as digits as its factorization.

42403114214113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 42403114214113 its reverse (31141241130424), we get a palindrome (73544355344537).

The spelling of 42403114214113 in words is "forty-two trillion, four hundred three billion, one hundred fourteen million, two hundred fourteen thousand, one hundred thirteen".