Base | Representation |
---|---|
bin | 1100010110001100010… |
… | …01010001001011000101 |
3 | 1111120000101200110200202 |
4 | 12023012021101023011 |
5 | 23422311131112123 |
6 | 522520013020245 |
7 | 42435561652352 |
oct | 6130611211305 |
9 | 1446011613622 |
10 | 424231113413 |
11 | 153a08449568 |
12 | 6a276184685 |
13 | 3100a796683 |
14 | 1676639d629 |
15 | b07dd3ca28 |
hex | 62c62512c5 |
424231113413 has 4 divisors (see below), whose sum is σ = 424235906688. Its totient is φ = 424226320140.
The previous prime is 424231113373. The next prime is 424231113491. The reversal of 424231113413 is 314311132424.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-424231113413 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (424231112413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2261333 + ... + 2441738.
It is an arithmetic number, because the mean of its divisors is an integer number (106058976672).
Almost surely, 2424231113413 is an apocalyptic number.
It is an amenable number.
424231113413 is a deficient number, since it is larger than the sum of its proper divisors (4793275).
424231113413 is an equidigital number, since it uses as much as digits as its factorization.
424231113413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4793274.
The product of its digits is 6912, while the sum is 29.
Adding to 424231113413 its reverse (314311132424), we get a palindrome (738542245837).
The spelling of 424231113413 in words is "four hundred twenty-four billion, two hundred thirty-one million, one hundred thirteen thousand, four hundred thirteen".
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