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424334000113 = 1992077242551
BaseRepresentation
bin1100010110011000100…
…01101111111111110001
31111120021120021122201021
412023030101233333301
523423014001000423
6522534130135441
742441251326522
oct6131421577761
91446246248637
10424334000113
11153a605318a1
126a2a4721581
1331025bab08a
1416775d02849
15b087db295d
hex62cc46fff1

424334000113 has 8 divisors (see below), whose sum is σ = 446674061120. Its totient is φ = 401994608400.

The previous prime is 424334000099. The next prime is 424334000147. The reversal of 424334000113 is 311000433424.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 424334000113 - 221 = 424331902961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (424334000173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1628188 + ... + 1870738.

It is an arithmetic number, because the mean of its divisors is an integer number (55834257640).

Almost surely, 2424334000113 is an apocalyptic number.

It is an amenable number.

424334000113 is a deficient number, since it is larger than the sum of its proper divisors (22340061007).

424334000113 is a wasteful number, since it uses less digits than its factorization.

424334000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334647.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 424334000113 its reverse (311000433424), we get a palindrome (735334433537).

The spelling of 424334000113 in words is "four hundred twenty-four billion, three hundred thirty-four million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 19 92077 242551 1749463 4608469 22333368427 424334000113