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4255854534301 is a prime number
BaseRepresentation
bin111101111011100100101…
…100101001111010011101
3120001212002211010201022011
4331323210230221322131
51024211442230044201
613015040152351221
7616322020445026
oct75734454517235
916055084121264
104255854534301
1113a0996a31117
125889910a5511
1324b42ca812b6
14109dad4d5c4d
1575a87c76151
hex3dee4b29e9d

4255854534301 has 2 divisors, whose sum is σ = 4255854534302. Its totient is φ = 4255854534300.

The previous prime is 4255854534229. The next prime is 4255854534331. The reversal of 4255854534301 is 1034354585524.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4047544446201 + 208310088100 = 2011851^2 + 456410^2 .

It is a cyclic number.

It is not a de Polignac number, because 4255854534301 - 211 = 4255854532253 is a prime.

It is a super-3 number, since 3×42558545343013 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4255854534331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2127927267150 + 2127927267151.

It is an arithmetic number, because the mean of its divisors is an integer number (2127927267151).

Almost surely, 24255854534301 is an apocalyptic number.

It is an amenable number.

4255854534301 is a deficient number, since it is larger than the sum of its proper divisors (1).

4255854534301 is an equidigital number, since it uses as much as digits as its factorization.

4255854534301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760000, while the sum is 49.

The spelling of 4255854534301 in words is "four trillion, two hundred fifty-five billion, eight hundred fifty-four million, five hundred thirty-four thousand, three hundred one".