Base | Representation |
---|---|
bin | 11001011001011… |
… | …111100001101011 |
3 | 1002200210210022211 |
4 | 121121133201223 |
5 | 1333041110011 |
6 | 110141025551 |
7 | 13362621223 |
oct | 3131374153 |
9 | 1080723284 |
10 | 426113131 |
11 | 1a9591114 |
12 | ba8552b7 |
13 | 6a385362 |
14 | 40841083 |
15 | 27620b21 |
hex | 1965f86b |
426113131 has 4 divisors (see below), whose sum is σ = 427003200. Its totient is φ = 425223064.
The previous prime is 426113113. The next prime is 426113141. The reversal of 426113131 is 131311624.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 426113131 - 27 = 426113003 is a prime.
It is a super-2 number, since 2×4261131312 = 363144800821246322, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (426113141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 444316 + ... + 445273.
It is an arithmetic number, because the mean of its divisors is an integer number (106750800).
Almost surely, 2426113131 is an apocalyptic number.
426113131 is a deficient number, since it is larger than the sum of its proper divisors (890069).
426113131 is an equidigital number, since it uses as much as digits as its factorization.
426113131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 890068.
The product of its digits is 432, while the sum is 22.
The square root of 426113131 is about 20642.5078660515. The cubic root of 426113131 is about 752.5031215862.
Adding to 426113131 its reverse (131311624), we get a palindrome (557424755).
The spelling of 426113131 in words is "four hundred twenty-six million, one hundred thirteen thousand, one hundred thirty-one".
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