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4262254556413 = 71741349737799
BaseRepresentation
bin111110000001100010001…
…010110011010011111101
3120002110121211220112011011
4332001202022303103331
51024313044131301123
613022015215155221
7616636432646440
oct76014212632375
916073554815134
104262254556413
1113a3680642497
1258a078515b11
1324bc0c998729
1410a4194b3657
1575d0ea78e0d
hex3e0622b34fd

4262254556413 has 8 divisors (see below), whose sum is σ = 4873945980800. Its totient is φ = 3651262611120.

The previous prime is 4262254556411. The next prime is 4262254556489. The reversal of 4262254556413 is 3146554522624.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4262254556413 - 21 = 4262254556411 is a prime.

It is a super-3 number, since 3×42622545564133 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4262254556411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 174856713 + ... + 174881086.

It is an arithmetic number, because the mean of its divisors is an integer number (609243247600).

Almost surely, 24262254556413 is an apocalyptic number.

It is an amenable number.

4262254556413 is a deficient number, since it is larger than the sum of its proper divisors (611691424387).

4262254556413 is a wasteful number, since it uses less digits than its factorization.

4262254556413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 349739547.

The product of its digits is 6912000, while the sum is 49.

The spelling of 4262254556413 in words is "four trillion, two hundred sixty-two billion, two hundred fifty-four million, five hundred fifty-six thousand, four hundred thirteen".

Divisors: 1 7 1741 12187 349737799 2448164593 608893508059 4262254556413