4263155047 has 2 divisors, whose sum is σ = 4263155048. Its totient is φ = 4263155046.

The previous prime is 4263155033. The next prime is 4263155107. The reversal of 4263155047 is 7405513624.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4263155047 is a prime.

It is a super-3 number, since 3×4263155047³ (a number of 30 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4263154997 and 4263155015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4263153047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2131577523 + 2131577524.

It is an arithmetic number, because the mean of its divisors is an integer number (2131577524).

Almost surely, 2^4263155047 is an apocalyptic number.

4263155047 is a deficient number, since it is larger than the sum of its proper divisors (1).

4263155047 is an equidigital number, since it uses as much as digits as its factorization.

4263155047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 37.

The square root of 4263155047 is about 65292.8407024844. The cubic root of 4263155047 is about 1621.4754437697.

The spelling of 4263155047 in words is "four billion, two hundred sixty-three million, one hundred fifty-five thousand, forty-seven".