Base | Representation |
---|---|
bin | 111110000011011110100… |
… | …011001110110101011101 |
3 | 120002200000021112212202101 |
4 | 332003132203032311131 |
5 | 1024331332340213024 |
6 | 13023002242125101 |
7 | 620042232200242 |
oct | 76033643166535 |
9 | 16080007485671 |
10 | 4264341335389 |
11 | 13a4551570413 |
12 | 58a55b350791 |
13 | 24c1831078a5 |
14 | 10a5766bb5c9 |
15 | 75dd2d7dc44 |
hex | 3e0de8ced5d |
4264341335389 has 2 divisors, whose sum is σ = 4264341335390. Its totient is φ = 4264341335388.
The previous prime is 4264341335329. The next prime is 4264341335431. The reversal of 4264341335389 is 9835331434624.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2750678639289 + 1513662696100 = 1658517^2 + 1230310^2 .
It is a cyclic number.
It is not a de Polignac number, because 4264341335389 - 215 = 4264341302621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4264341335329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2132170667694 + 2132170667695.
It is an arithmetic number, because the mean of its divisors is an integer number (2132170667695).
Almost surely, 24264341335389 is an apocalyptic number.
It is an amenable number.
4264341335389 is a deficient number, since it is larger than the sum of its proper divisors (1).
4264341335389 is an equidigital number, since it uses as much as digits as its factorization.
4264341335389 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 22394880, while the sum is 55.
The spelling of 4264341335389 in words is "four trillion, two hundred sixty-four billion, three hundred forty-one million, three hundred thirty-five thousand, three hundred eighty-nine".
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