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426931616197 = 1922470085063
BaseRepresentation
bin1100011011001110001…
…10110111100111000101
31111210222121011020002101
412031213012313213011
523443323443204242
6524044002112101
742562522601332
oct6154706674705
91453877136071
10426931616197
11155073849249
126a8aa64b631
133134b0c7c08
1416940cc3989
15b18ae719b7
hex63671b79c5

426931616197 has 4 divisors (see below), whose sum is σ = 449401701280. Its totient is φ = 404461531116.

The previous prime is 426931616183. The next prime is 426931616203. The reversal of 426931616197 is 791616139624.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 426931616197 - 211 = 426931614149 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (426931616107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11235042513 + ... + 11235042550.

It is an arithmetic number, because the mean of its divisors is an integer number (112350425320).

Almost surely, 2426931616197 is an apocalyptic number.

It is an amenable number.

426931616197 is a deficient number, since it is larger than the sum of its proper divisors (22470085083).

426931616197 is a wasteful number, since it uses less digits than its factorization.

426931616197 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22470085082.

The product of its digits is 2939328, while the sum is 55.

The spelling of 426931616197 in words is "four hundred twenty-six billion, nine hundred thirty-one million, six hundred sixteen thousand, one hundred ninety-seven".

Divisors: 1 19 22470085063 426931616197