Base | Representation |
---|---|
bin | 111110010011101111110… |
… | …110010000010101011001 |
3 | 120011100002210120022202001 |
4 | 332103233312100111121 |
5 | 1030123122204412441 |
6 | 13035011554241001 |
7 | 621231164264236 |
oct | 76235766202531 |
9 | 16140083508661 |
10 | 4281811404121 |
11 | 14009a6a02649 |
12 | 591a15b86161 |
13 | 250a08603474 |
14 | 10b3529a078d |
15 | 765a695a731 |
hex | 3e4efd90559 |
4281811404121 has 2 divisors, whose sum is σ = 4281811404122. Its totient is φ = 4281811404120.
The previous prime is 4281811404119. The next prime is 4281811404127. The reversal of 4281811404121 is 1214041181824.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3977774958096 + 304036446025 = 1994436^2 + 551395^2 .
It is a cyclic number.
It is not a de Polignac number, because 4281811404121 - 21 = 4281811404119 is a prime.
Together with 4281811404119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4281811404127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2140905702060 + 2140905702061.
It is an arithmetic number, because the mean of its divisors is an integer number (2140905702061).
Almost surely, 24281811404121 is an apocalyptic number.
It is an amenable number.
4281811404121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4281811404121 is an equidigital number, since it uses as much as digits as its factorization.
4281811404121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16384, while the sum is 37.
Adding to 4281811404121 its reverse (1214041181824), we get a palindrome (5495852585945).
The spelling of 4281811404121 in words is "four trillion, two hundred eighty-one billion, eight hundred eleven million, four hundred four thousand, one hundred twenty-one".
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