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42832149380513 is a prime number
BaseRepresentation
bin10011011110100101000110…
…00011000111110110100001
312121122201021010122100101222
421233102203003013312201
521103230220220134023
6231032452350304425
712010343406424133
oct1157224303076641
9177581233570358
1042832149380513
111271401576a009
1249791a81b8115
131ab909255a87c
14a81130d9b053
154e4268683cc8
hex26f4a30c7da1

42832149380513 has 2 divisors, whose sum is σ = 42832149380514. Its totient is φ = 42832149380512.

The previous prime is 42832149380437. The next prime is 42832149380549. The reversal of 42832149380513 is 31508394123824.

42832149380513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21416097829009 + 21416051551504 = 4627753^2 + 4627748^2 .

It is a cyclic number.

It is not a de Polignac number, because 42832149380513 - 238 = 42557271473569 is a prime.

It is not a weakly prime, because it can be changed into another prime (42832149380593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21416074690256 + 21416074690257.

It is an arithmetic number, because the mean of its divisors is an integer number (21416074690257).

Almost surely, 242832149380513 is an apocalyptic number.

It is an amenable number.

42832149380513 is a deficient number, since it is larger than the sum of its proper divisors (1).

42832149380513 is an equidigital number, since it uses as much as digits as its factorization.

42832149380513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4976640, while the sum is 53.

The spelling of 42832149380513 in words is "forty-two trillion, eight hundred thirty-two billion, one hundred forty-nine million, three hundred eighty thousand, five hundred thirteen".