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4300031534431 is a prime number
BaseRepresentation
bin111110100100101101110…
…110100010010101011111
3120020002010120221211210011
4332210231312202111133
51030422431033100211
613051223543024051
7622444534654543
oct76445566422537
916202116854704
104300031534431
1114086a6777186
1259545ba3b027
13252650318869
1410c1a072da23
1576cc12e7921
hex3e92dda255f

4300031534431 has 2 divisors, whose sum is σ = 4300031534432. Its totient is φ = 4300031534430.

The previous prime is 4300031534399. The next prime is 4300031534563. The reversal of 4300031534431 is 1344351300034.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4300031534431 - 25 = 4300031534399 is a prime.

It is a super-2 number, since 2×43000315344312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4300031534393 and 4300031534402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4300031534231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150015767215 + 2150015767216.

It is an arithmetic number, because the mean of its divisors is an integer number (2150015767216).

Almost surely, 24300031534431 is an apocalyptic number.

4300031534431 is a deficient number, since it is larger than the sum of its proper divisors (1).

4300031534431 is an equidigital number, since it uses as much as digits as its factorization.

4300031534431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 4300031534431 its reverse (1344351300034), we get a palindrome (5644382834465).

The spelling of 4300031534431 in words is "four trillion, three hundred billion, thirty-one million, five hundred thirty-four thousand, four hundred thirty-one".