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4300216121401 = 40731055785937
BaseRepresentation
bin111110100100111000110…
…110101011100000111001
3120020002121110021211111121
4332210320312223200321
51030423320311341101
613051254135225241
7622452235636144
oct76447066534071
916202543254447
104300216121401
1114087909920a2
125954b1818221
1325267c637515
1410c1bb05d05b
1576cd260a0a1
hex3e938dab839

4300216121401 has 4 divisors (see below), whose sum is σ = 4301271911412. Its totient is φ = 4299160331392.

The previous prime is 4300216121359. The next prime is 4300216121417. The reversal of 4300216121401 is 1041216120034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 144305775376 + 4155910346025 = 379876^2 + 2038605^2 .

It is a cyclic number.

It is not a de Polignac number, because 4300216121401 - 215 = 4300216088633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4300216121471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 527888896 + ... + 527897041.

It is an arithmetic number, because the mean of its divisors is an integer number (1075317977853).

Almost surely, 24300216121401 is an apocalyptic number.

It is an amenable number.

4300216121401 is a deficient number, since it is larger than the sum of its proper divisors (1055790011).

4300216121401 is a wasteful number, since it uses less digits than its factorization.

4300216121401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1055790010.

The product of its (nonzero) digits is 1152, while the sum is 25.

The spelling of 4300216121401 in words is "four trillion, three hundred billion, two hundred sixteen million, one hundred twenty-one thousand, four hundred one".

Divisors: 1 4073 1055785937 4300216121401