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430022260403137 is a prime number
BaseRepresentation
bin110000111000110100101110…
…0000100111010101111000001
32002101120201121200211112001101
41201301221130010322233001
5422330441042130400022
64122325255455534401
7156402040326541213
oct14161513404725701
92071521550745041
10430022260403137
11115022464382036
1240291240b2a401
13155c3c0475487c
14782928d19c5b3
1534aacec322627
hex1871a5c13abc1

430022260403137 has 2 divisors, whose sum is σ = 430022260403138. Its totient is φ = 430022260403136.

The previous prime is 430022260403111. The next prime is 430022260403159. The reversal of 430022260403137 is 731304062220034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 423080305415056 + 6941954988081 = 20568916^2 + 2634759^2 .

It is a cyclic number.

It is not a de Polignac number, because 430022260403137 - 247 = 289284772047809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 430022260403096 and 430022260403105.

It is not a weakly prime, because it can be changed into another prime (430022260403107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215011130201568 + 215011130201569.

It is an arithmetic number, because the mean of its divisors is an integer number (215011130201569).

Almost surely, 2430022260403137 is an apocalyptic number.

It is an amenable number.

430022260403137 is a deficient number, since it is larger than the sum of its proper divisors (1).

430022260403137 is an equidigital number, since it uses as much as digits as its factorization.

430022260403137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 37.

The spelling of 430022260403137 in words is "four hundred thirty trillion, twenty-two billion, two hundred sixty million, four hundred three thousand, one hundred thirty-seven".