Base | Representation |
---|---|
bin | 10011100011100010000101… |
… | …10111001001011001110001 |
3 | 12122020222112121122001010211 |
4 | 21301301002313021121301 |
5 | 21114022240041221431 |
6 | 231242555532224121 |
7 | 12025546634513152 |
oct | 1161610267113161 |
9 | 178228477561124 |
10 | 43002334320241 |
11 | 1277a20772312a |
12 | 49a618290b041 |
13 | 1acc1448c803a |
14 | a89477415929 |
15 | 4e88c93612b1 |
hex | 271c42dc9671 |
43002334320241 has 2 divisors, whose sum is σ = 43002334320242. Its totient is φ = 43002334320240.
The previous prime is 43002334320233. The next prime is 43002334320269. The reversal of 43002334320241 is 14202343320034.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22634082185841 + 20368252134400 = 4757529^2 + 4513120^2 .
It is a cyclic number.
It is not a de Polignac number, because 43002334320241 - 23 = 43002334320233 is a prime.
It is not a weakly prime, because it can be changed into another prime (43002334320641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21501167160120 + 21501167160121.
It is an arithmetic number, because the mean of its divisors is an integer number (21501167160121).
Almost surely, 243002334320241 is an apocalyptic number.
It is an amenable number.
43002334320241 is a deficient number, since it is larger than the sum of its proper divisors (1).
43002334320241 is an equidigital number, since it uses as much as digits as its factorization.
43002334320241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 43002334320241 its reverse (14202343320034), we get a palindrome (57204677640275).
The spelling of 43002334320241 in words is "forty-three trillion, two billion, three hundred thirty-four million, three hundred twenty thousand, two hundred forty-one".
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