Base | Representation |
---|---|
bin | 101000000011001111… |
… | …010001111010000101 |
3 | 11010000000122001200110 |
4 | 220003033101322011 |
5 | 1201033011310432 |
6 | 31431125103233 |
7 | 3051452024535 |
oct | 500317217205 |
9 | 133000561613 |
10 | 43004010117 |
11 | 17268708332 |
12 | 8401b57b19 |
13 | 409453c143 |
14 | 211d5394c5 |
15 | 11ba5bddcc |
hex | a033d1e85 |
43004010117 has 16 divisors (see below), whose sum is σ = 58140050048. Its totient is φ = 28268870400.
The previous prime is 43004010103. The next prime is 43004010121. The reversal of 43004010117 is 71101040034.
It is not a de Polignac number, because 43004010117 - 26 = 43004010053 is a prime.
It is a super-2 number, since 2×430040101172 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43004010093 and 43004010102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43004014117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 838617 + ... + 888417.
It is an arithmetic number, because the mean of its divisors is an integer number (3633753128).
Almost surely, 243004010117 is an apocalyptic number.
It is an amenable number.
43004010117 is a deficient number, since it is larger than the sum of its proper divisors (15136039931).
43004010117 is a wasteful number, since it uses less digits than its factorization.
43004010117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53820.
The product of its (nonzero) digits is 336, while the sum is 21.
The spelling of 43004010117 in words is "forty-three billion, four million, ten thousand, one hundred seventeen".
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