43004225113 has 4 divisors (see below), whose sum is σ = 43006439140. Its totient is φ = 43002011088.

The previous prime is 43004225071. The next prime is 43004225129. The reversal of 43004225113 is 31152240034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10810176784 + 32194048329 = 103972^2 + 179427^2 .

It is a cyclic number.

It is not a de Polignac number, because 43004225113 - 2¹⁷ = 43004094041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43004225153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1077618 + ... + 1116811.

It is an arithmetic number, because the mean of its divisors is an integer number (10751609785).

Almost surely, 2^43004225113 is an apocalyptic number.

It is an amenable number.

43004225113 is a deficient number, since it is larger than the sum of its proper divisors (2214027).

43004225113 is a wasteful number, since it uses less digits than its factorization.

43004225113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2214026.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 43004225113 its reverse (31152240034), we get a palindrome (74156465147).

The spelling of 43004225113 in words is "forty-three billion, four million, two hundred twenty-five thousand, one hundred thirteen".