Base | Representation |
---|---|
bin | 110000111000111110100100… |
… | …0010110011111001101010101 |
3 | 2002101122202012020210211100212 |
4 | 1201301331020112133031111 |
5 | 422331312343000114031 |
6 | 4122343113531015205 |
7 | 156403416311652551 |
oct | 14161751026371525 |
9 | 2071582166724325 |
10 | 430043404301141 |
11 | 115030424579604 |
12 | 40295361b9a505 |
13 | 155c5bc4110017 |
14 | 782a2d736c861 |
15 | 34ab6386e612b |
hex | 1871f4859f355 |
430043404301141 has 4 divisors (see below), whose sum is σ = 432226365744492. Its totient is φ = 427860442857792.
The previous prime is 430043404301081. The next prime is 430043404301167. The reversal of 430043404301141 is 141103404340034.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 272062889160241 + 157980515140900 = 16494329^2 + 12569030^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-430043404301141 is a prime.
It is a super-2 number, since 2×4300434043011412 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 430043404301098 and 430043404301107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (430043404301171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1091480721380 + ... + 1091480721773.
It is an arithmetic number, because the mean of its divisors is an integer number (108056591436123).
Almost surely, 2430043404301141 is an apocalyptic number.
It is an amenable number.
430043404301141 is a deficient number, since it is larger than the sum of its proper divisors (2182961443351).
430043404301141 is a wasteful number, since it uses less digits than its factorization.
430043404301141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2182961443350.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 430043404301141 its reverse (141103404340034), we get a palindrome (571146808641175).
The spelling of 430043404301141 in words is "four hundred thirty trillion, forty-three billion, four hundred four million, three hundred one thousand, one hundred forty-one".
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