43010131 has 2 divisors, whose sum is σ = 43010132. Its totient is φ = 43010130.

The previous prime is 43010117. The next prime is 43010137. The reversal of 43010131 is 13101034.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43010131 - 2⁷ = 43010003 is a prime.

It is a super-2 number, since 2×43010131² = 3699742737274322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (43010137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505065 + 21505066.

It is an arithmetic number, because the mean of its divisors is an integer number (21505066).

Almost surely, 2^43010131 is an apocalyptic number.

43010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

43010131 is an equidigital number, since it uses as much as digits as its factorization.

43010131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 43010131 is about 6558.2109603153. The cubic root of 43010131 is about 350.3673177741.

Adding to 43010131 its reverse (13101034), we get a palindrome (56111165).

The spelling of 43010131 in words is "forty-three million, ten thousand, one hundred thirty-one".