Base | Representation |
---|---|
bin | 110000111001011110111111… |
… | …0011000101110011001011001 |
3 | 2002101220101220121110202211010 |
4 | 1201302331332120232121121 |
5 | 422333432441231142131 |
6 | 4122435110502324133 |
7 | 156411432565324245 |
oct | 14162757630563131 |
9 | 2071811817422733 |
10 | 430113030334041 |
11 | 115057a0366665a |
12 | 402a6953729649 |
13 | 155cc63bc2c462 |
14 | 782d820439425 |
15 | 34ad361086b46 |
hex | 1872f7e62e659 |
430113030334041 has 8 divisors (see below), whose sum is σ = 573507954641664. Its totient is φ = 286730063124560.
The previous prime is 430113030334037. The next prime is 430113030334073. The reversal of 430113030334041 is 140433030311034.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 430113030334041 - 22 = 430113030334037 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (430113030334541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2989190601 + ... + 2989334486.
It is an arithmetic number, because the mean of its divisors is an integer number (71688494330208).
Almost surely, 2430113030334041 is an apocalyptic number.
It is an amenable number.
430113030334041 is a deficient number, since it is larger than the sum of its proper divisors (143394924307623).
430113030334041 is a wasteful number, since it uses less digits than its factorization.
430113030334041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5978549071.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 430113030334041 its reverse (140433030311034), we get a palindrome (570546060645075).
The spelling of 430113030334041 in words is "four hundred thirty trillion, one hundred thirteen billion, thirty million, three hundred thirty-four thousand, forty-one".
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