Base | Representation |
---|---|
bin | 110000111001011111000001… |
… | …0100111100100001000101111 |
3 | 2002101220102002120001220010122 |
4 | 1201302332002213210020233 |
5 | 422333433112420124124 |
6 | 4122435121520155155 |
7 | 156411434416651355 |
oct | 14162760247441057 |
9 | 2071812076056118 |
10 | 430113101333039 |
11 | 115057a3a74a213 |
12 | 402a6973468abb |
13 | 155cc65085a8b7 |
14 | 782d829a3b7d5 |
15 | 34ad36740d75e |
hex | 1872f829e422f |
430113101333039 has 2 divisors, whose sum is σ = 430113101333040. Its totient is φ = 430113101333038.
The previous prime is 430113101332861. The next prime is 430113101333081. The reversal of 430113101333039 is 930333101311034.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-430113101333039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (430113101333089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215056550666519 + 215056550666520.
It is an arithmetic number, because the mean of its divisors is an integer number (215056550666520).
Almost surely, 2430113101333039 is an apocalyptic number.
430113101333039 is a deficient number, since it is larger than the sum of its proper divisors (1).
430113101333039 is an equidigital number, since it uses as much as digits as its factorization.
430113101333039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 35.
The spelling of 430113101333039 in words is "four hundred thirty trillion, one hundred thirteen billion, one hundred one million, three hundred thirty-three thousand, thirty-nine".
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