Base | Representation |
---|---|
bin | 101000000011101011… |
… | …100101011001110001 |
3 | 11010000112121000211222 |
4 | 220003223211121301 |
5 | 1201041411230001 |
6 | 31431552114425 |
7 | 3051602060051 |
oct | 500353453161 |
9 | 133015530758 |
10 | 43011430001 |
11 | 17271915a71 |
12 | 8404535a15 |
13 | 4095c394c7 |
14 | 212050b561 |
15 | 11bb08761b |
hex | a03ae5671 |
43011430001 has 2 divisors, whose sum is σ = 43011430002. Its totient is φ = 43011430000.
The previous prime is 43011429971. The next prime is 43011430013. The reversal of 43011430001 is 10003411034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42261491776 + 749938225 = 205576^2 + 27385^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43011430001 is a prime.
It is a super-2 number, since 2×430114300012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43011430801) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505715000 + 21505715001.
It is an arithmetic number, because the mean of its divisors is an integer number (21505715001).
Almost surely, 243011430001 is an apocalyptic number.
It is an amenable number.
43011430001 is a deficient number, since it is larger than the sum of its proper divisors (1).
43011430001 is an equidigital number, since it uses as much as digits as its factorization.
43011430001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 43011430001 its reverse (10003411034), we get a palindrome (53014841035).
The spelling of 43011430001 in words is "forty-three billion, eleven million, four hundred thirty thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •