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43011430001 is a prime number
BaseRepresentation
bin101000000011101011…
…100101011001110001
311010000112121000211222
4220003223211121301
51201041411230001
631431552114425
73051602060051
oct500353453161
9133015530758
1043011430001
1117271915a71
128404535a15
134095c394c7
14212050b561
1511bb08761b
hexa03ae5671

43011430001 has 2 divisors, whose sum is σ = 43011430002. Its totient is φ = 43011430000.

The previous prime is 43011429971. The next prime is 43011430013. The reversal of 43011430001 is 10003411034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42261491776 + 749938225 = 205576^2 + 27385^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43011430001 is a prime.

It is a super-2 number, since 2×430114300012 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43011430801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505715000 + 21505715001.

It is an arithmetic number, because the mean of its divisors is an integer number (21505715001).

Almost surely, 243011430001 is an apocalyptic number.

It is an amenable number.

43011430001 is a deficient number, since it is larger than the sum of its proper divisors (1).

43011430001 is an equidigital number, since it uses as much as digits as its factorization.

43011430001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 43011430001 its reverse (10003411034), we get a palindrome (53014841035).

The spelling of 43011430001 in words is "forty-three billion, eleven million, four hundred thirty thousand, one".