Base | Representation |
---|---|
bin | 101000000011101101… |
… | …111011001000111011 |
3 | 11010000120202012011121 |
4 | 220003231323020323 |
5 | 1201042040341243 |
6 | 31432013210111 |
7 | 3051610223134 |
oct | 500355731073 |
9 | 133016665147 |
10 | 43012043323 |
11 | 172721a4847 |
12 | 8404790937 |
13 | 40960c2712 |
14 | 212062ac8b |
15 | 11bb1591ed |
hex | a03b7b23b |
43012043323 has 2 divisors, whose sum is σ = 43012043324. Its totient is φ = 43012043322.
The previous prime is 43012043299. The next prime is 43012043341. The reversal of 43012043323 is 32334021034.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43012043323 is a prime.
It is not a weakly prime, because it can be changed into another prime (43012043023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506021661 + 21506021662.
It is an arithmetic number, because the mean of its divisors is an integer number (21506021662).
Almost surely, 243012043323 is an apocalyptic number.
43012043323 is a deficient number, since it is larger than the sum of its proper divisors (1).
43012043323 is an equidigital number, since it uses as much as digits as its factorization.
43012043323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 43012043323 its reverse (32334021034), we get a palindrome (75346064357).
The spelling of 43012043323 in words is "forty-three billion, twelve million, forty-three thousand, three hundred twenty-three".
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