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43012043341 is a prime number
BaseRepresentation
bin101000000011101101…
…111011001001001101
311010000120202012012021
4220003231323021031
51201042040341331
631432013210141
73051610223161
oct500355731115
9133016665167
1043012043341
11172721a4863
128404790951
1340960c2727
14212062aca1
1511bb159211
hexa03b7b24d

43012043341 has 2 divisors, whose sum is σ = 43012043342. Its totient is φ = 43012043340.

The previous prime is 43012043323. The next prime is 43012043357. The reversal of 43012043341 is 14334021034.

43012043341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42995681316 + 16362025 = 207354^2 + 4045^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43012043341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43012043141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506021670 + 21506021671.

It is an arithmetic number, because the mean of its divisors is an integer number (21506021671).

Almost surely, 243012043341 is an apocalyptic number.

It is an amenable number.

43012043341 is a deficient number, since it is larger than the sum of its proper divisors (1).

43012043341 is an equidigital number, since it uses as much as digits as its factorization.

43012043341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 43012043341 its reverse (14334021034), we get a palindrome (57346064375).

The spelling of 43012043341 in words is "forty-three billion, twelve million, forty-three thousand, three hundred forty-one".