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43012222146031 is a prime number
BaseRepresentation
bin10011100011110100100000…
…01110001101010111101111
312122021221001201022122011211
421301322100032031113233
521114203012332133111
6231251313030455251
712026346650606455
oct1161722016152757
9178257051278154
1043012222146031
1112783421090a86
1249a8082204527
131b0005c29b628
14a89b346d89d5
154e8ca7462521
hex271e9038d5ef

43012222146031 has 2 divisors, whose sum is σ = 43012222146032. Its totient is φ = 43012222146030.

The previous prime is 43012222145801. The next prime is 43012222146037. The reversal of 43012222146031 is 13064122221034.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43012222146031 - 223 = 43012213757423 is a prime.

It is a super-2 number, since 2×430122221460312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43012222145984 and 43012222146002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43012222146037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506111073015 + 21506111073016.

It is an arithmetic number, because the mean of its divisors is an integer number (21506111073016).

Almost surely, 243012222146031 is an apocalyptic number.

43012222146031 is a deficient number, since it is larger than the sum of its proper divisors (1).

43012222146031 is an equidigital number, since it uses as much as digits as its factorization.

43012222146031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 43012222146031 its reverse (13064122221034), we get a palindrome (56076344367065).

The spelling of 43012222146031 in words is "forty-three trillion, twelve billion, two hundred twenty-two million, one hundred forty-six thousand, thirty-one".