Base | Representation |
---|---|
bin | 111110100101111001011… |
… | …110111101001100011001 |
3 | 120020012102000120222110212 |
4 | 332211321132331030121 |
5 | 1030433030401441101 |
6 | 13051553511420505 |
7 | 622521143222504 |
oct | 76457136751431 |
9 | 16205360528425 |
10 | 4301300421401 |
11 | 1409197a537a5 |
12 | 595754984735 |
13 | 2527c317c059 |
14 | 10c28107213b |
15 | 76d478de1bb |
hex | 3e9797bd319 |
4301300421401 has 4 divisors (see below), whose sum is σ = 4304601497472. Its totient is φ = 4297999345332.
The previous prime is 4301300421337. The next prime is 4301300421449. The reversal of 4301300421401 is 1041240031034.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4301300421401 - 26 = 4301300421337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4301300420401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1650536081 + ... + 1650538686.
It is an arithmetic number, because the mean of its divisors is an integer number (1076150374368).
Almost surely, 24301300421401 is an apocalyptic number.
It is an amenable number.
4301300421401 is a deficient number, since it is larger than the sum of its proper divisors (3301076071).
4301300421401 is a wasteful number, since it uses less digits than its factorization.
4301300421401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3301076070.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4301300421401 its reverse (1041240031034), we get a palindrome (5342540452435).
The spelling of 4301300421401 in words is "four trillion, three hundred one billion, three hundred million, four hundred twenty-one thousand, four hundred one".
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