Base | Representation |
---|---|
bin | 10011100011110110000001… |
… | …01011011111110100000001 |
3 | 12122022000011101002111200101 |
4 | 21301323000223133310001 |
5 | 21114211143443130423 |
6 | 231251525431522401 |
7 | 12026406052061446 |
oct | 1161730053376401 |
9 | 178260141074611 |
10 | 43013035130113 |
11 | 127837a8a8aa54 |
12 | 49a826a529401 |
13 | 1b0015b8493b9 |
14 | a89bb06839cd |
15 | 4e8d03a017ad |
hex | 271ec0adfd01 |
43013035130113 has 2 divisors, whose sum is σ = 43013035130114. Its totient is φ = 43013035130112.
The previous prime is 43013035130099. The next prime is 43013035130147. The reversal of 43013035130113 is 31103153031034.
43013035130113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33393466149264 + 9619568980849 = 5778708^2 + 3101543^2 .
It is a cyclic number.
It is not a de Polignac number, because 43013035130113 - 25 = 43013035130081 is a prime.
It is a super-2 number, since 2×430130351301132 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43013035131113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506517565056 + 21506517565057.
It is an arithmetic number, because the mean of its divisors is an integer number (21506517565057).
Almost surely, 243013035130113 is an apocalyptic number.
It is an amenable number.
43013035130113 is a deficient number, since it is larger than the sum of its proper divisors (1).
43013035130113 is an equidigital number, since it uses as much as digits as its factorization.
43013035130113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4860, while the sum is 28.
Adding to 43013035130113 its reverse (31103153031034), we get a palindrome (74116188161147).
The spelling of 43013035130113 in words is "forty-three trillion, thirteen billion, thirty-five million, one hundred thirty thousand, one hundred thirteen".
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