43013104041 has 8 divisors (see below), whose sum is σ = 57353458720. Its totient is φ = 28674076032.

The previous prime is 43013104037. The next prime is 43013104051. The reversal of 43013104041 is 14040131034.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 43013104041 - 2² = 43013104037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43013103999 and 43013104017.

It is not an unprimeable number, because it can be changed into a prime (43013104021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 253375 + ... + 387588.

It is an arithmetic number, because the mean of its divisors is an integer number (7169182340).

Almost surely, 2^43013104041 is an apocalyptic number.

It is an amenable number.

43013104041 is a deficient number, since it is larger than the sum of its proper divisors (14340354679).

43013104041 is a wasteful number, since it uses less digits than its factorization.

43013104041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 663335.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 43013104041 its reverse (14040131034), we get a palindrome (57053235075).

The spelling of 43013104041 in words is "forty-three billion, thirteen million, one hundred four thousand, forty-one".