Base | Representation |
---|---|
bin | 10011100011110110011100… |
… | …11111001011001101101111 |
3 | 12122022000202111222121000022 |
4 | 21301323032133023031233 |
5 | 21114212132243443124 |
6 | 231252004424552355 |
7 | 12026414564061542 |
oct | 1161731637131557 |
9 | 178260674877008 |
10 | 43013266781039 |
11 | 127839078207a5 |
12 | 49a83140226bb |
13 | 1b00197835c59 |
14 | a89bd3344859 |
15 | 4e8d1900dc5e |
hex | 271ece7cb36f |
43013266781039 has 2 divisors, whose sum is σ = 43013266781040. Its totient is φ = 43013266781038.
The previous prime is 43013266781029. The next prime is 43013266781053. The reversal of 43013266781039 is 93018766231034.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43013266781039 - 212 = 43013266776943 is a prime.
It is a super-2 number, since 2×430132667810392 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43013266781029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506633390519 + 21506633390520.
It is an arithmetic number, because the mean of its divisors is an integer number (21506633390520).
Almost surely, 243013266781039 is an apocalyptic number.
43013266781039 is a deficient number, since it is larger than the sum of its proper divisors (1).
43013266781039 is an equidigital number, since it uses as much as digits as its factorization.
43013266781039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3919104, while the sum is 53.
The spelling of 43013266781039 in words is "forty-three trillion, thirteen billion, two hundred sixty-six million, seven hundred eighty-one thousand, thirty-nine".
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