43014113 has 2 divisors, whose sum is σ = 43014114. Its totient is φ = 43014112.

The previous prime is 43014079. The next prime is 43014137. The reversal of 43014113 is 31141034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21743569 + 21270544 = 4663^2 + 4612^2 .

It is a cyclic number.

It is not a de Polignac number, because 43014113 - 2⁸ = 43013857 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43014091 and 43014100.

It is not a weakly prime, because it can be changed into another prime (43017113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21507056 + 21507057.

It is an arithmetic number, because the mean of its divisors is an integer number (21507057).

Almost surely, 2^43014113 is an apocalyptic number.

It is an amenable number.

43014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43014113 is an equidigital number, since it uses as much as digits as its factorization.

43014113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 43014113 is about 6558.5145421810. The cubic root of 43014113 is about 350.3781301073.

Adding to 43014113 its reverse (31141034), we get a palindrome (74155147).

The spelling of 43014113 in words is "forty-three million, fourteen thousand, one hundred thirteen".