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4301411434132 = 221075352858533
BaseRepresentation
bin111110100110000000000…
…110011011111010010100
3120020012200202111000022111
4332212000012123322110
51030433242311343012
613052012515040404
7622523661633001
oct76460006337224
916205622430274
104301411434132
11140924468725a
12595785ba0104
1325281017a367
1410c291acc8a8
1576d5251bba7
hex3e98019be94

4301411434132 has 6 divisors (see below), whose sum is σ = 7527470009738. Its totient is φ = 2150705717064.

The previous prime is 4301411434129. The next prime is 4301411434181. The reversal of 4301411434132 is 2314341141034.

It can be written as a sum of positive squares in only one way, i.e., 2650787759376 + 1650623674756 = 1628124^2 + 1284766^2 .

It is a junction number, because it is equal to n+sod(n) for n = 4301411434094 and 4301411434103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 537676429263 + ... + 537676429270.

Almost surely, 24301411434132 is an apocalyptic number.

It is an amenable number.

4301411434132 is a deficient number, since it is larger than the sum of its proper divisors (3226058575606).

4301411434132 is a wasteful number, since it uses less digits than its factorization.

4301411434132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1075352858537 (or 1075352858535 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4301411434132 its reverse (2314341141034), we get a palindrome (6615752575166).

The spelling of 4301411434132 in words is "four trillion, three hundred one billion, four hundred eleven million, four hundred thirty-four thousand, one hundred thirty-two".

Divisors: 1 2 4 1075352858533 2150705717066 4301411434132