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43014120217 is a prime number
BaseRepresentation
bin101000000011110101…
…110110001100011001
311010000201122201010121
4220003311312030121
51201043103321332
631432125513241
73051633663205
oct500365661431
9133021581117
1043014120217
1117273393192
128405412821
13409666bb53
142120a0bb05
1511bb419797
hexa03d76319

43014120217 has 2 divisors, whose sum is σ = 43014120218. Its totient is φ = 43014120216.

The previous prime is 43014120199. The next prime is 43014120257. The reversal of 43014120217 is 71202141034.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29991658761 + 13022461456 = 173181^2 + 114116^2 .

It is a cyclic number.

It is not a de Polignac number, because 43014120217 - 219 = 43013595929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43014120191 and 43014120200.

It is not a weakly prime, because it can be changed into another prime (43014120257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21507060108 + 21507060109.

It is an arithmetic number, because the mean of its divisors is an integer number (21507060109).

Almost surely, 243014120217 is an apocalyptic number.

It is an amenable number.

43014120217 is a deficient number, since it is larger than the sum of its proper divisors (1).

43014120217 is an equidigital number, since it uses as much as digits as its factorization.

43014120217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

The spelling of 43014120217 in words is "forty-three billion, fourteen million, one hundred twenty thousand, two hundred seventeen".