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43023130042 = 221511565021
BaseRepresentation
bin101000000100011000…
…001101110110111010
311010001100121110021211
4220010120031312322
51201102410130132
631433050553334
73052103400004
oct500430156672
9133040543254
1043023130042
1117278487422
12840843884a
1340984a4ac9
142121cb5374
1511bc0e9147
hexa0460ddba

43023130042 has 4 divisors (see below), whose sum is σ = 64534695066. Its totient is φ = 21511565020.

The previous prime is 43023130037. The next prime is 43023130067. The reversal of 43023130042 is 24003132034.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 28116917761 + 14906212281 = 167681^2 + 122091^2 .

It is a super-2 number, since 2×430231300422 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43023129995 and 43023130022.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10755782509 + ... + 10755782512.

Almost surely, 243023130042 is an apocalyptic number.

43023130042 is a deficient number, since it is larger than the sum of its proper divisors (21511565024).

43023130042 is a wasteful number, since it uses less digits than its factorization.

43023130042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21511565023.

The product of its (nonzero) digits is 1728, while the sum is 22.

Adding to 43023130042 its reverse (24003132034), we get a palindrome (67026262076).

The spelling of 43023130042 in words is "forty-three billion, twenty-three million, one hundred thirty thousand, forty-two".

Divisors: 1 2 21511565021 43023130042