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43024130041 is a prime number
BaseRepresentation
bin101000000100011100…
…000001111111111001
311010001102111021000211
4220010130001333321
51201103134130131
631433124231121
73052115033314
oct500434017771
9133042437024
1043024130041
1117278aaa772
12840883b4a1
134098765019
14212209597b
1511bc2455b1
hexa04701ff9

43024130041 has 2 divisors, whose sum is σ = 43024130042. Its totient is φ = 43024130040.

The previous prime is 43024130029. The next prime is 43024130047. The reversal of 43024130041 is 14003142034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24391880041 + 18632250000 = 156179^2 + 136500^2 .

It is a cyclic number.

It is not a de Polignac number, because 43024130041 - 215 = 43024097273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43024129994 and 43024130021.

It is not a weakly prime, because it can be changed into another prime (43024130047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21512065020 + 21512065021.

It is an arithmetic number, because the mean of its divisors is an integer number (21512065021).

Almost surely, 243024130041 is an apocalyptic number.

It is an amenable number.

43024130041 is a deficient number, since it is larger than the sum of its proper divisors (1).

43024130041 is an equidigital number, since it uses as much as digits as its factorization.

43024130041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 43024130041 its reverse (14003142034), we get a palindrome (57027272075).

The spelling of 43024130041 in words is "forty-three billion, twenty-four million, one hundred thirty thousand, forty-one".