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430324121412431 is a prime number
BaseRepresentation
bin110000111011000001010010…
…0011001010010001101001111
32002102122120202220120121121122
41201312002210121102031033
5422400412300040144211
64123120101112551155
7156432614613020621
oct14166024431221517
92072576686517548
10430324121412431
11115129487013144
124031b8456b24bb
131561650ccb49bc
147839b27538c11
1534b3ab808b6db
hex18760a465234f

430324121412431 has 2 divisors, whose sum is σ = 430324121412432. Its totient is φ = 430324121412430.

The previous prime is 430324121412421. The next prime is 430324121412499. The reversal of 430324121412431 is 134214121423034.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 430324121412431 - 246 = 359955377234767 is a prime.

It is a super-2 number, since 2×4303241214124312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 430324121412391 and 430324121412400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (430324121412421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215162060706215 + 215162060706216.

It is an arithmetic number, because the mean of its divisors is an integer number (215162060706216).

Almost surely, 2430324121412431 is an apocalyptic number.

430324121412431 is a deficient number, since it is larger than the sum of its proper divisors (1).

430324121412431 is an equidigital number, since it uses as much as digits as its factorization.

430324121412431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 430324121412431 its reverse (134214121423034), we get a palindrome (564538242835465).

The spelling of 430324121412431 in words is "four hundred thirty trillion, three hundred twenty-four billion, one hundred twenty-one million, four hundred twelve thousand, four hundred thirty-one".