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4303241431411 = 131392381428573
BaseRepresentation
bin111110100111101101001…
…011010100100101110011
3120020101102021221111122111
4332213231023110211303
51031001014301301121
613052514250150151
7622620222435016
oct76475513244563
916211367844574
104303241431411
111409aa366a2aa
12595bb6a22357
13252a423410a0
1410c3c6b7337d
1576e0ceed2e1
hex3e9ed2d4973

4303241431411 has 8 divisors (see below), whose sum is σ = 4667600005040. Its totient is φ = 3943645715232.

The previous prime is 4303241431381. The next prime is 4303241431429. The reversal of 4303241431411 is 1141341423034.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4303241431411 - 217 = 4303241300339 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4303241131411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1190712480 + ... + 1190716093.

It is an arithmetic number, because the mean of its divisors is an integer number (583450000630).

Almost surely, 24303241431411 is an apocalyptic number.

4303241431411 is a deficient number, since it is larger than the sum of its proper divisors (364358573629).

4303241431411 is a wasteful number, since it uses less digits than its factorization.

4303241431411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2381428725.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4303241431411 its reverse (1141341423034), we get a palindrome (5444582854445).

The spelling of 4303241431411 in words is "four trillion, three hundred three billion, two hundred forty-one million, four hundred thirty-one thousand, four hundred eleven".

Divisors: 1 13 139 1807 2381428573 30958571449 331018571647 4303241431411