Base | Representation |
---|---|
bin | 111110100111110001011… |
… | …010001011001111011110 |
3 | 120020101121020112211002021 |
4 | 332213301122023033132 |
5 | 1031001140440343032 |
6 | 13052525304050354 |
7 | 622622044106041 |
oct | 76476132131736 |
9 | 16211536484067 |
10 | 4303312434142 |
11 | 140a02a755747 |
12 | 5960167639ba |
13 | 252a53c71137 |
14 | 10c3d2376c58 |
15 | 76e14376097 |
hex | 3e9f168b3de |
4303312434142 has 8 divisors (see below), whose sum is σ = 6497716788432. Its totient is φ = 2137406838000.
The previous prime is 4303312434133. The next prime is 4303312434193. The reversal of 4303312434142 is 2414342133034.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×43033124341422 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4303312434098 and 4303312434107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7124689159 + ... + 7124689762.
It is an arithmetic number, because the mean of its divisors is an integer number (812214598554).
Almost surely, 24303312434142 is an apocalyptic number.
4303312434142 is a deficient number, since it is larger than the sum of its proper divisors (2194404354290).
4303312434142 is a wasteful number, since it uses less digits than its factorization.
4303312434142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14249379074.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 4303312434142 its reverse (2414342133034), we get a palindrome (6717654567176).
The spelling of 4303312434142 in words is "four trillion, three hundred three billion, three hundred twelve million, four hundred thirty-four thousand, one hundred forty-two".
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