Base | Representation |
---|---|
bin | 111110100111110001100… |
… | …000001110011010110101 |
3 | 120020101121100112101111112 |
4 | 332213301200032122311 |
5 | 1031001141342120041 |
6 | 13052525402044405 |
7 | 622622063432432 |
oct | 76476140163265 |
9 | 16211540471445 |
10 | 4303314020021 |
11 | 140a030639195 |
12 | 5960171a9705 |
13 | 252a543a7c23 |
14 | 10c3d266ab89 |
15 | 76e1458adeb |
hex | 3e9f180e6b5 |
4303314020021 has 16 divisors (see below), whose sum is σ = 4510114775040. Its totient is φ = 4100808705840.
The previous prime is 4303314019999. The next prime is 4303314020023. The reversal of 4303314020021 is 1200204133034.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4303314020021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4303314020023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5195360 + ... + 5966438.
It is an arithmetic number, because the mean of its divisors is an integer number (281882173440).
Almost surely, 24303314020021 is an apocalyptic number.
It is an amenable number.
4303314020021 is a deficient number, since it is larger than the sum of its proper divisors (206800755019).
4303314020021 is a wasteful number, since it uses less digits than its factorization.
4303314020021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 773864.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 4303314020021 its reverse (1200204133034), we get a palindrome (5503518153055).
The spelling of 4303314020021 in words is "four trillion, three hundred three billion, three hundred fourteen million, twenty thousand, twenty-one".
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