43040034341333 has 4 divisors (see below), whose sum is σ = 43042132954380. Its totient is φ = 43037935728288.

The previous prime is 43040034341287. The next prime is 43040034341389. The reversal of 43040034341333 is 33314343004034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27836102136049 + 15203932205284 = 5275993^2 + 3899222^2 .

It is a cyclic number.

It is not a de Polignac number, because 43040034341333 - 2⁸ = 43040034341077 is a prime.

It is a super-2 number, since 2×43040034341333² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43040034341293 and 43040034341302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43040034341833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1049275760 + ... + 1049316777.

It is an arithmetic number, because the mean of its divisors is an integer number (10760533238595).

Almost surely, 2^{43040034341333} is an apocalyptic number.

It is an amenable number.

43040034341333 is a deficient number, since it is larger than the sum of its proper divisors (2098613047).

43040034341333 is a wasteful number, since it uses less digits than its factorization.

43040034341333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2098613046.

The product of its (nonzero) digits is 186624, while the sum is 35.

Adding to 43040034341333 its reverse (33314343004034), we get a palindrome (76354377345367).

The spelling of 43040034341333 in words is "forty-three trillion, forty billion, thirty-four million, three hundred forty-one thousand, three hundred thirty-three".