43040113 has 2 divisors, whose sum is σ = 43040114. Its totient is φ = 43040112.

The previous prime is 43040083. The next prime is 43040117. The reversal of 43040113 is 31104034.

43040113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42419169 + 620944 = 6513^2 + 788^2 .

It is a cyclic number.

It is not a de Polignac number, because 43040113 - 2¹³ = 43031921 is a prime.

It is a super-3 number, since 3×43040113³ (a number of 24 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (43040117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21520056 + 21520057.

It is an arithmetic number, because the mean of its divisors is an integer number (21520057).

Almost surely, 2^43040113 is an apocalyptic number.

It is an amenable number.

43040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43040113 is an equidigital number, since it uses as much as digits as its factorization.

43040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 43040113 is about 6560.4963989015. The cubic root of 43040113 is about 350.4487115659.

Adding to 43040113 its reverse (31104034), we get a palindrome (74144147).

The spelling of 43040113 in words is "forty-three million, forty thousand, one hundred thirteen".