430401331 has 2 divisors, whose sum is σ = 430401332. Its totient is φ = 430401330.

The previous prime is 430401263. The next prime is 430401371. The reversal of 430401331 is 133104034.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 430401331 - 2¹⁷ = 430270259 is a prime.

It is a super-2 number, since 2×430401331² = 370490611453143122, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 430401299 and 430401308.

It is not a weakly prime, because it can be changed into another prime (430401371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215200665 + 215200666.

It is an arithmetic number, because the mean of its divisors is an integer number (215200666).

Almost surely, 2^430401331 is an apocalyptic number.

430401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

430401331 is an equidigital number, since it uses as much as digits as its factorization.

430401331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 430401331 is about 20746.1160461422. The cubic root of 430401331 is about 755.0189788075.

Adding to 430401331 its reverse (133104034), we get a palindrome (563505365).

The spelling of 430401331 in words is "four hundred thirty million, four hundred one thousand, three hundred thirty-one".