Base | Representation |
---|---|
bin | 1100100001101100001… |
… | …01000001000000110011 |
3 | 1112010221121002022120021 |
4 | 12100312011001000303 |
5 | 24022431411423011 |
6 | 525420323424311 |
7 | 43044545520430 |
oct | 6206605010063 |
9 | 1463847068507 |
10 | 430404014131 |
11 | 156595933203 |
12 | 6b4b9525097 |
13 | 3178261bb50 |
14 | 16b90138b87 |
15 | b2e0c2a471 |
hex | 6436141033 |
430404014131 has 16 divisors (see below), whose sum is σ = 557608441600. Its totient is φ = 322616310048.
The previous prime is 430404014119. The next prime is 430404014149. The reversal of 430404014131 is 131410404034.
It is not a de Polignac number, because 430404014131 - 25 = 430404014099 is a prime.
It is a super-2 number, since 2×4304040141312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 430404014096 and 430404014105.
It is not an unprimeable number, because it can be changed into a prime (430404014101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 124464441 + ... + 124467898.
It is an arithmetic number, because the mean of its divisors is an integer number (34850527600).
Almost surely, 2430404014131 is an apocalyptic number.
430404014131 is a deficient number, since it is larger than the sum of its proper divisors (127204427469).
430404014131 is a wasteful number, since it uses less digits than its factorization.
430404014131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248932378.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 430404014131 its reverse (131410404034), we get a palindrome (561814418165).
The spelling of 430404014131 in words is "four hundred thirty billion, four hundred four million, fourteen thousand, one hundred thirty-one".
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