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430413411122417 is a prime number
BaseRepresentation
bin110000111011101010110111…
…0011110011111110011110001
32002102222010020122220212000102
41201313111232132133303301
5422403343131221404132
64123225105201202145
7156442225366025042
oct14167255636376361
92072863218825012
10430413411122417
111151633367a6898
1240335004630355
1315621a6c904018
147840197d808c9
1534b6091db1c62
hex187756e79fcf1

430413411122417 has 2 divisors, whose sum is σ = 430413411122418. Its totient is φ = 430413411122416.

The previous prime is 430413411122381. The next prime is 430413411122419. The reversal of 430413411122417 is 714221114314034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 423185830533361 + 7227580589056 = 20571481^2 + 2688416^2 .

It is a cyclic number.

It is not a de Polignac number, because 430413411122417 - 212 = 430413411118321 is a prime.

Together with 430413411122419, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (430413411122419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215206705561208 + 215206705561209.

It is an arithmetic number, because the mean of its divisors is an integer number (215206705561209).

Almost surely, 2430413411122417 is an apocalyptic number.

It is an amenable number.

430413411122417 is a deficient number, since it is larger than the sum of its proper divisors (1).

430413411122417 is an equidigital number, since it uses as much as digits as its factorization.

430413411122417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 38.

The spelling of 430413411122417 in words is "four hundred thirty trillion, four hundred thirteen billion, four hundred eleven million, one hundred twenty-two thousand, four hundred seventeen".