Base | Representation |
---|---|
bin | 1100100001110111110… |
… | …11010001111101100001 |
3 | 1112011012102200212221022 |
4 | 12100323323101331201 |
5 | 24023132021003114 |
6 | 525434150335225 |
7 | 43050146455226 |
oct | 6207373217541 |
9 | 1464172625838 |
10 | 430502125409 |
11 | 156636254704 |
12 | 6b52635a515 |
13 | 31799a50a65 |
14 | 16b9d19794d |
15 | b2e965a48e |
hex | 643bed1f61 |
430502125409 has 2 divisors, whose sum is σ = 430502125410. Its totient is φ = 430502125408.
The previous prime is 430502125379. The next prime is 430502125411. The reversal of 430502125409 is 904521205034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 430430469184 + 71656225 = 656072^2 + 8465^2 .
It is a cyclic number.
It is not a de Polignac number, because 430502125409 - 224 = 430485348193 is a prime.
Together with 430502125411, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (430502125909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215251062704 + 215251062705.
It is an arithmetic number, because the mean of its divisors is an integer number (215251062705).
Almost surely, 2430502125409 is an apocalyptic number.
It is an amenable number.
430502125409 is a deficient number, since it is larger than the sum of its proper divisors (1).
430502125409 is an equidigital number, since it uses as much as digits as its factorization.
430502125409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 430502125409 in words is "four hundred thirty billion, five hundred two million, one hundred twenty-five thousand, four hundred nine".
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